Huawei Honor V8 Max 4G with 6.6-inch QHD display spotted on TENNA

Huawei’s new device with model number EDI-DL00 has been spotted on TENNA which is expected to be called the Honor V8 Max. We’ve already seen the likes of Xiaomi and Asus launching their plus sized phablets with the Mi Max and Zenfone 3 Ultra, and now Huawei’s sub-brand Honor is venturing into this space with the 6.6-inch Honor V8 Max.

Key specifications of the Honor V8 Max include a 6.6-inch Quad-HD AMOLED display, a Kirin 950 octa-core chipset bundled with 3GB of RAM. The device comes with 32GB of internal storage further expandable up to 128GB via microSD slot. The dual-SIM phablet will also offer 4G LTE along with VoLTE. In addition, there’s also a fingerprint sensor housed on the back slightly below the primary camera unit.

In terms of optics, the Honor V8 Max will feature a 13MP primary camera with dual tone LED flash along with an 8MP front-facing camera for capturing selfies. Juicing up the device would be a massive 4,400mAh battery that should at least offer a day of usage. It is also expected to get support for fast charging as we’ve seen with the Honor V8.

The device weighs a rather chunky 219 grams and measures 178.8 x 90.9 x 7.2mm, which makes it a bit handful though manageable nonetheless.

The Honor V8 Max¬†will run Android 6.0 Marshmallow out-of-the-box bundled with the company’s latest EMUI 4.1 skin. There’s no information regarding the phablet’s price and availability as of now, though we expect to hear more on July 8 when the company launches the Honor 8.